Question 3. Prove that the following are irrationals: (i) 1/?2 (ii) 7?5 (iii) 6 + ?2 Chapter 1: Real Numbers Maths Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 3. Prove that the following are irrationals: (i) 1/√2 (ii) 7√5 (iii) 6 + √2 is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 1 absolutely free. NCERT Solutions for class 10 Maths Chapter 1: Real Numbers is very essencial for getting good marks in CBSE Board examinations
Question 3. Prove that the following are irrationals:
(i) 1/√2 (ii) 7√5 (iii) 6 + √2
Answer:
(i) Let take that 1/√2 is a rational number.
So we can write this number as
1/√2 = a/b
Here a and b are two co prime number and b is not equal to 0
Multiply by √2 both sides we get
1 = (a√2)/b
Now multiply by b
b = a√2
divide by a we get
b/a = √2
Here a and b are integer so b/a is a rational number so √2 should be a rational number But √2 is a irrational number so it is contradict
Hence result is 1/√2 is a irrational number
(ii) Let take that 7√5 is a rational number.
So we can write this number as
7√5 = a/b
Here a and b are two co prime number and b is not equal to 0
Divide by 7 we get
√5) =a/(7b)
Here a and b are integer so a/7b is a rational number so √5 should be a rational number but √5 is a irrational number so it is contradict
Hence result is 7√5 is a irrational number.
(iii) Let take that 6 + √2 is a rational number.
So we can write this number as
6 + √2 = a/b
Here a and b are two co prime number and b is not equal to 0
Subtract 6 both side we get
√2 = a/b – 6
√2 = (a-6b)/b
Here a and b are integer so (a-6b)/b is a rational number so √2 should be a rational number But √2 is a irrational number so it is contradict
Hence result is 6 + √2 is a irrational number
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